81u^2-72u+16=0

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Solution for 81u^2-72u+16=0 equation: 



81u^2-72u+16=0

a = 81; b = -72; c = +16;
Δ = b2-4ac
Δ = -722-4·81·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{72}{162}=4/9$

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